(2x^2+3x-5)/(x^2-1)

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Solution for (2x^2+3x-5)/(x^2-1) equation: 


D( x )

x^2-1 = 0

x^2-1 = 0

x^2-1 = 0

1*x^2 = 1 // : 1

x^2 = 1

x^2 = 1 // ^ 1/2

abs(x) = 1

x = 1 or x = -1

x in (-oo:-1) U (-1:1) U (1:+oo)

(2*x^2+3*x-5)/(x^2-1) = 0

2*x^2+3*x-5 = 0

2*x^2+3*x-5 = 0

DELTA = 3^2-(-5*2*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)-3)/(2*2) or x = (-49^(1/2)-3)/(2*2)

x = 1 or x = -5/2

(x+5/2)*(x-1) = 0

((x+5/2)*(x-1))/(x^2-1) = 0

( x+5/2 )

x+5/2 = 0 // - 5/2

x = -5/2

( x-1 )

x-1 = 0 // + 1

x = 1

x in { 1} 

x = -5/2

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